Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - Get Ready! - Page 661: 5



Work Step by Step

First, we can get rid of $m^2$ from both the numerator and the denominator. $\frac{p^{-3}q^{4}}{p^2q^{-2}}$ $\frac{p^{-3}}{q^{-2}}$ is the same as $\frac{q^2}{p^3}$. $\frac{q^2q^4}{p^2p^3}$ $\boxed{\frac{q^6}{p^5}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.