## Algebra 1: Common Core (15th Edition)

$\boxed{\frac{q^6}{p^5}}$
First, we can get rid of $m^2$ from both the numerator and the denominator. $\frac{p^{-3}q^{4}}{p^2q^{-2}}$ $\frac{p^{-3}}{q^{-2}}$ is the same as $\frac{q^2}{p^3}$. $\frac{q^2q^4}{p^2p^3}$ $\boxed{\frac{q^6}{p^5}}$