Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - Get Ready! - Page 661: 17


$g=-\frac{1}{2}$ or $g=\frac{5}{3}$

Work Step by Step

$6g^2-7g=5$ $6g^2-7g-5=0$ $6g^2-10g+3g-5=0$ $2g(3g-5)+(3g-5)=0$ $(2g+1)(3g-5)=0$ $2g+1=0$ or $3g-5=0$ $2g=-1$ or $3g=5$ $g=-\frac{1}{2}$ or $g=\frac{5}{3}$
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