Answer
$=\frac{2}{7}$
Work Step by Step
Applying power rules:
$\frac{(3a^2)^3(2b^{-1})^2}{(7a^3)^2(3b^{2})^{-1}}$
$=\frac{3a^62b^{-2}}{7a^63b^{-2}}$
$=\frac{3.2}{7.3}$
$=\frac{2}{7}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - Get Ready! - Page 661: 6
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
