Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - Get Ready! - Page 661: 6



Work Step by Step

Applying power rules: $\frac{(3a^2)^3(2b^{-1})^2}{(7a^3)^2(3b^{2})^{-1}}$ $=\frac{3a^62b^{-2}}{7a^63b^{-2}}$ $=\frac{3.2}{7.3}$ $=\frac{2}{7}$
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