Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - Get Ready! - Page 661: 20

Answer

$x=4$

Work Step by Step

$\sqrt x+2=x$ $\sqrt x=x-2$ $(\sqrt x)^2=(x-2)^2$ $x=x^2-4x+4$ $0=x^2-5x+4$ $x^2-4x-x+4=0$ $x(x-4)-(x-4)=0$ $(x-1)(x-4)=0$ $x-1=0$ or $x-4=0$ $x=1$ or $x=4$ Check for extraneous solutions: $\sqrt {1}+2=3,1=1$ (eliminate this solution) $\sqrt 4+2=4$ (keep this solution)
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