Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 637: 43


The solution is $x=3$.

Work Step by Step

$\sqrt 5x+10=5$ Square both sides: $(\sqrt 5x+10)^2=5^2$ $5x=15$ $x=3$ With $x=3$ then $\sqrt 5x+10=5$ $\sqrt 5(3)+10=5$ $5=5$ Hence, the solution is $x=3$.
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