Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 637: 27


There are no extraneous solutions.

Work Step by Step

$y=\sqrt 2y$ With $y=0$ then $0=\sqrt 2(0)$ $0 = 0$ With $y=2$ then $2=\sqrt 2*2$ $2=2$ Hence, there are no extraneous solutions.
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