Answer
The solution is $d=4$.
Work Step by Step
$\sqrt d+12=d$
Square both sides:
$(\sqrt d+12)^2=d^2$
$d^2-d-12=0$
$(d-4)(d+3)=0$
$d=4$ or $d=-3$
With $d=4$
then $\sqrt 4+12=4$
$4=4$
With $d=-3$
then $\sqrt -3+12=-3$
$3=-3$
Hence, the solution is $d=4$.