Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 637: 28


$a=\frac{-1}{2}$ is extraneous.

Work Step by Step

$2a=\sqrt 4a+3$ With $a=\frac{3}{2}$ then $2(\frac{3}{2})=\sqrt 4(\frac{3}{2})+3$ $3=3$ With $a=\frac{-1}{2}$ then $2(\frac{-1}{2})=\sqrt 4(\frac{-1}{2})+3$ $-1 \ne 1$ traneous.Hence, $a=\frac{-1}{2}$ is ex
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