Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 630: 55

Answer

$4\sqrt 3+3\sqrt 2+3\sqrt 6+6$

Work Step by Step

$\frac{2\sqrt 12+3\sqrt 6}{\sqrt 9-\sqrt 6}$ Multiply the equation with $\frac{\sqrt 9+\sqrt 6}{\sqrt 9+\sqrt 6}$ $=\frac{(2\sqrt 12+3\sqrt 6)(\sqrt 9+\sqrt 6)}{9-6}$ $=\frac{12\sqrt 3+12\sqrt 2+9\sqrt 6+18}{3}$ $=4\sqrt 3+4\sqrt 2+3\sqrt 6+6$
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