Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 630: 41


The answer is: $x=(\sqrt7-1)\div4$.

Work Step by Step

Given: $x/(2+\sqrt7)=(3-\sqrt7)/4$ By cross multiplication we get, $4*x=(3-\sqrt7)*(2+\sqrt7)$ $4x=(3*2+3\sqrt7-2\sqrt7-\sqrt7^{2})$ $4x=(6+\sqrt7-7)$ $x=(\sqrt7-1)\div4$
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