Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 630: 48

Answer

$6\sqrt 2+6\sqrt 3$

Work Step by Step

Applying the rules of radicals: $3\sqrt2 (2+\sqrt 6)$ $=6\sqrt 2+3\sqrt 12$ $=6\sqrt 2+6\sqrt 3$
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