Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 10 - Radical Expressions and Equations - 10-3 Operations With Radical Expressions - Practice and Problem-Solving Exercises - Page 630: 39


The answer is $x=-4/3$.

Work Step by Step

Given: $3/(1+\sqrt5)=(1-\sqrt5)/x$ By cross multiplication, $3*x=(1-\sqrt5)*(1+\sqrt5)$ $3x=1^{2}-\sqrt5^{2}$ $3x=1-5$. $x=-4/3$.
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