Answer
a) (¬1 · ¬0) + (1 · ¬0) = 1
b) (¬T ∧ ¬F) ∨ (T ∧ ¬F) ≡ T
Work Step by Step
) We compute,
(¬1 · ¬0) + (1 · ¬0)
= (0 · 1) + (1 · 1)
= 0 + 1
= 1
b) Following the instructions, we have (¬T ∧ ¬F) ∨ (T ∧ ¬F) ≡ T
Discrete Mathematics and Its Applications, Seventh Edition
by Rosen, Kenneth
Published by
McGraw-Hill Education
ISBN 10:
0073383090
ISBN 13:
978-0-07338-309-5
Chapter 12 - Section 12.1 - Boolean Functions - Exercises - Page 818: 4
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