Answer
a) Showing that (1 · 1) + (0 · 1 + 0) = 1.
b) Translating the equation in part (a) into a propositional
equivalence by changing each 0 into an F, each 1
into a T, each Boolean sum into a disjunction, each
Boolean product into a conjunction, each complementation
into a negation, and the equals sign into a propositional
equivalence sign.
Work Step by Step
"~" sign mean the value is inverted
a)
(1 · 1) + (~(0 · 1) + 0)
= 1 + (~0 + 0)
= 1 + (1 + 0)
= 1 + 1 = 1
b)
(T ∧ T) ∨ (¬(F ∧ T) ∨ F) ≡ T
