Answer
Showing that you obtain De Morgan’s laws for propositions when you transform De Morgan’s laws for Boolean algebra in Table 6 into logical
equivalences.
Work Step by Step
If we replace each 0 by F, 1 by T, Boolean sum by ∨,
-Boolean product by ∧, and by ¬ (and x by p and y by q so that the variables look like they represent propositions,
-and the equals
sign by the logical equivalence symbol),
- then xy = x + becomes ¬(p ∧ q) ≡ ¬p ∨ ¬q
and
x + y = x y becomes ¬(p ∨q) ≡ ¬p∧¬q.
