Fundamentals of Engineering Thermodynamics 8th Edition

Published by Wiley
ISBN 10: 1118412931
ISBN 13: 978-1-11841-293-0

Chapter 2 - Problems: Developing Engineering Skills - Page 81: 2.8

Answer

$\bigtriangleup KE = -347.22KJ$ $\bigtriangleup PE = 441.450KJ$

Work Step by Step

$\large m=900kg;\large v_2 = 0;\large v_1 = 100km/hr = 27.77m/sec$ $\bigtriangleup KE = (1/2)*m*(v_2^2-v_1^2)$ $\bigtriangleup KE = (1/2)*900*(0^2-27.77^2)$ $\bigtriangleup KE = -347.22KJ$ $\bigtriangleup PE = mg(z_2-z_1$ $\large m = 900kg; g=9.81m/sec^2;z_2 = 50m;z_1=0m$ $\bigtriangleup PE = 900*9.81*(50-0) = 441.450kJ$
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