Fundamentals of Engineering Thermodynamics 8th Edition

Published by Wiley
ISBN 10: 1118412931
ISBN 13: 978-1-11841-293-0

Chapter 2 - Problems: Developing Engineering Skills - Page 81: 2.7

Answer

$\bigtriangleup KE = 207623 KJ$ $\bigtriangleup PE = 1369200 KJ$

Work Step by Step

$\bigtriangleup KE = (1/2)m(v_2^2-v_1^2) $ $m=14000kg;v_2 = 620km/hr = 172.22m/sec;v_1 = 0$ $\bigtriangleup KE = (1/2)*14000*(172.22^2-0^2) $ $\bigtriangleup KE = 207623 KJ$ $\bigtriangleup PE = mg(z_2-z_1)$ $m=14000kg;g = 9.78;z_2=10000;z_1 = 0$ $\bigtriangleup PE = 14000*9.78*(10000-0)$ $\bigtriangleup PE = 1369200 KJ$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.