Chapter 2 - Problems: Developing Engineering Skills - Page 81: 2.5

$12185ft$

$\bigtriangleup PE = 2.25*10^4Btu$ $F_g = 2500lbf$ $z_1=5183ft$ $\bigtriangleup PE = mg(z_2-z_1)$ $F_g = mg$ $\frac{\bigtriangleup PE}{mg} = \frac{2.25*10^4Btu}{2500lbf} \frac{778ft.lbf}{1lbf} = 7002ft $ $z_2 = \frac{\bigtriangleup PE}{mg}+z_1$ $z_2 = 7002+5183 = 12185ft$