Answer
$\bigtriangleup KE = -4800 KJ$
Work Step by Step
$\bigtriangleup KE =(1/2)m(v_2^2-v_1^2)$
$v_1 = 100;v_2 = 20;m=1000kg$
$\bigtriangleup KE =(0.5)1000(20^2-100^2)$
$\bigtriangleup KE= -4800000J = -4800 KJ$
Fundamentals of Engineering Thermodynamics 8th Edition
by Moran, Michael J.; Shapiro, Howard N.; Boettner, Daisie D.; Bailey, Margaret B.
Published by
Wiley
ISBN 10:
1118412931
ISBN 13:
978-1-11841-293-0
Chapter 2 - Problems: Developing Engineering Skills - Page 81: 2.6
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