Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 17 - Planar Kinetics of a Rigid Body: Force and Acceleration - Section 17.1 - Mass Moment of Inertia - Problems: 18

Answer

$I_{O}=6.23$ kg*m$^2$

Work Step by Step

$m_{square}=(1.40)(1.40)(0.05)(50)=4.19$ kg $m_{circle}=(\pi)(0.15)^2(0.05)(50)=1.77$ kg $I_{O}=\Sigma I_{G}+md^2=(\frac{1}{12})(4.9)(2)(1.40)^2-(\frac{1}{2})(0.177)(0.15)^2+(4.9-0.177)(1.4sin(45[{\deg}]))$ $=6.23$ kg*m$^2$
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