Answer
$k=2.17$ m
Work Step by Step
$I_{O}=\Sigma I_{G}+md^2=(\frac{1}{12})(2)^2(2)+(2)(1)^2+(\frac{1}{2})(4)(0.5)^2+(4)(2.5)^2=28.17$ kg*m$^2$
$k=\sqrt{\frac{I_{O}}{m}}=\sqrt{\frac{28.17}{6}}=2.17$ m
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 17 - Planar Kinetics of a Rigid Body: Force and Acceleration - Section 17.1 - Mass Moment of Inertia - Problems - Page 421: 17
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