Answer
$I_{O}=1.36$ kg*m$^2$
Work Step by Step
$I_{O}=\Sigma I+md^2=[\frac{1}{12}(1.2)^2(3)(1.2)+3(1.2)(0.2)^2]+[(\frac{1}{12}(0.4)(3)(0.4)^2+(0.4)(3)(0.4)^2]=1.36$ kg*m$^2$
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 17 - Planar Kinetics of a Rigid Body: Force and Acceleration - Section 17.1 - Mass Moment of Inertia - Problems - Page 421: 15
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