Answer
$I_{O}=7.67$ kg*m^2
Work Step by Step
$I_{O}=\Sigma I_{G}+md^2=(2(\frac{1}{12}(4)(1)^2)+(10(0.5)^2)+18(0.5)^2=7.67$ kg*m^2
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 17 - Planar Kinetics of a Rigid Body: Force and Acceleration - Section 17.1 - Mass Moment of Inertia - Problems - Page 421: 14
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