Answer
$v=0.781$ m/s
Work Step by Step
$vdv=ads$
$\int_0^v vdv=\int_1^s\frac{1}{4}s^{\frac{1}{2}}ds$
$\frac{v^2}{2}|^v_0=\frac{1}{6}s^{\frac{3}{2}}|^s_1$
$v=\frac{1}{\sqrt{3}}(s^{\frac{3}{2}}-1)^{\frac{1}{2}}$ m/s
When $s=2$ m, $v=0.781$ m/s.
Engineering Mechanics: Statics & Dynamics (14th Edition)
by Hibbeler, Russell C.
Published by
Pearson
ISBN 10:
0133915425
ISBN 13:
978-0-13391-542-6
Chapter 12 - Kinematics of a Particle - Section 12.2 - Rectilinear Kinematics: Continuous Motion - Problems - Page 19: 24
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