## Engineering Mechanics: Statics & Dynamics (14th Edition)

$h_{alt}=314$ m $v=72.5$ m/s
$(+\downarrow)$ $s=s_0+v_0t+\frac{1}{2}a_ct^2$ $h=0+(-6)(8)+\frac{1}{2}(9.81)(8)^2$ $h=265.92m$ During $t=8$s, the balloon rises $h'=vt=6(8)=48$ m $h_{alt}=h+h'=265.92+48=314$ m $(+\downarrow)$ $v=v_0+a_ct$ $v=-6+9.81(8)=72.5$ m/s