#### Answer

$1.04kip$

#### Work Step by Step

We are given that a concrete column has a diameter of 350 mm and a length of 2 m and has a density of $2.45 Mg/m^3$. We are asked to determine the weight of the column in pounds.
First we find the volume of the cylinder.
$V=\pi r^2 h=\pi (.350m /2)^2 *2m= 0.1924 m^3$
Now we can find the weight:
$0.1924 m^3 *\frac{2.45Mg}{1m^3} * \frac{10^3kg}{1Mg}*\frac{2.20lb}{1kg}*\frac{1kip}{1000lb}=1.04kip$