Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 1 - General Principles - Problems: 4

Answer

(a). 271 Nm (b). $54.936 \frac{kN}{m^3}$ (c). 0.678 mm/s

Work Step by Step

(a). $200lb.ft \times \frac {4.448N}{1lb} \times \frac{1m}{3.28ft}=271 Nm$ (b). $350 \frac{lb}{ft^3} \frac{3.28^3ft^3}{1m^3}\frac{4.448N}{1lb}\times \frac{1kN}{1000N}=54.936 kN/m^3$ (c). $8ft/h \times \frac{1m}{3.28ft} \times \frac{1000mm}{1m} \times \frac {1h}{3600s}=0.677mm/s$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.