## Engineering Mechanics: Statics & Dynamics (14th Edition)

$101kPa$
First we are asked to convert 1 Pascal ($1Pa =1N/m^2$) to $lb/ft^2$. $1Pa= 1 N /m^2 * \frac{1lb}{4.4482N}* (\frac{0.3048m}{1ft})^2=20.9(10^-3)lb/ft^2$ We are asked to convert $14.7lb/in^2$ to Pascals $14.7lb/in^2* \frac{4.4482N}{1lb}* (\frac{12in}{1ft})^2* (\frac{1ft}{0.3048m})^2= 101(10^3) N/m^2=101(10^3) Pa$ or $101kPa$