Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 1 - General Principles - Problems: 16

Answer

$101kPa$

Work Step by Step

First we are asked to convert 1 Pascal ($1Pa =1N/m^2$) to $lb/ft^2$. $1Pa= 1 N /m^2 * \frac{1lb}{4.4482N}* (\frac{0.3048m}{1ft})^2=20.9(10^-3)lb/ft^2$ We are asked to convert $14.7lb/in^2$ to Pascals $14.7lb/in^2* \frac{4.4482N}{1lb}* (\frac{12in}{1ft})^2* (\frac{1ft}{0.3048m})^2= 101(10^3) N/m^2=101(10^3) Pa$ or $101kPa$
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