Engineering Mechanics: Statics & Dynamics (14th Edition)

Published by Pearson
ISBN 10: 0133915425
ISBN 13: 978-0-13391-542-6

Chapter 1 - General Principles - Problems - Page 15: 15


$7.41*\mu N$

Work Step by Step

First we will make sure the units in equation 1-2 are dimensionally homogeneous. $F=G \frac{m_1*m_2}{r}$ $F=(\frac{m^3}{kg*s^2}) \frac{kg*kg}{m}$ $F=kg *m^2 / s^2$ This checks out. These units are correct. Given that the mass of each sphere is 200 kg and the radius is 300 mm, we will find the gravitational force between them $F=G \frac{m_1*m_2}{r}$ $F=66.73*10^{-12} m^3 / kg / s^2*\frac{200kg *200kg}{0.600m}$ $F=7.41*10^{-6}N=7.41*\mu N$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.