Fundamentals of Electrical Engineering

Published by McGraw-Hill Education
ISBN 10: 0073380377
ISBN 13: 978-0-07338-037-7

Chapter 2 - Fundamentals of Electric Circuits - Part 1 Circuits - Homework Problems - Page 54: 2.33

Answer

5W, absorbed

Work Step by Step

Add the resistors in series to get 20 $\Omega$ The current through the loop is $\frac{20V}{20 \Omega} = 1A$ The power absorbed by the resistor is $P = I^2 *R = 1^2 *5 = 5 W$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.