Fundamentals of Electrical Engineering

Published by McGraw-Hill Education
ISBN 10: 0073380377
ISBN 13: 978-0-07338-037-7

Chapter 2 - Fundamentals of Electric Circuits - Part 1 Circuits - Homework Problems - Page 54: 2.31

Answer

$P=14.0625 W$ or $P=23.44W$

Work Step by Step

First calculate the Resistance of the first bulb using a power equation $P = V^2 /R$ $60 = 100^2 /R$ $R=166.667 Ohm$ Now do the same for the other bulb $100 = 100^2 /R$ $R=100 Ohm$ Calculate equivalent series resistance and find total current $I = 100/266.667$ $I=0.375A$ now use another power equation in terms of current and resistance to find power $P = I^2 *R$ for the first bulb $P = 0.375^2 *100 = 14.0625W$ next bulb $P = 0.375^2 * 166.667 = 23.4375W$
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