Fundamentals of Electrical Engineering

Published by McGraw-Hill Education
ISBN 10: 0073380377
ISBN 13: 978-0-07338-037-7

Chapter 2 - Fundamentals of Electric Circuits - Part 1 Circuits - Homework Problems - Page 54: 2.32

Answer

a.) 131.684 Ohm and 29.6485 Ohm b.) 367.55 W and 1632.5 W

Work Step by Step

Start by calculating the resistance of each configuration in terms of variables $R_1$ and $R_2$ Series: $ R = R1 + R2$ Parallel: $R = R1*R2/(R1 + R2)$ Series will have lowest power since it has highest resistance of the configurations Parallel will have the highest power since it has the lowest resistance Series: $ 300 = (220)^2 / (R1 + R2)$ Parallel: $2000 = 220^2 * (R1 + R2) /( R1*R2)$ 2 unknowns and 2 equations Solving for R1 and R2 in calculator gives: R1 = 131.684, R2 = 29.6485 Now use the equation $ P = V^2 /R$ to calculate the other powers R1 : $P = 220^2 / 131.68 = 367.55 W$ R2: $P = 220^2 / 29.6485 = 1632.5W$
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