Fundamentals of Electrical Engineering

Published by McGraw-Hill Education
ISBN 10: 0073380377
ISBN 13: 978-0-07338-037-7

Chapter 2 - Fundamentals of Electric Circuits - Part 1 Circuits - Homework Problems - Page 54: 2.30

Answer

$P = 11.111W$

Work Step by Step

First calculate the resistance of the bulb. $P = V^2 /R$ $100 = 110^2/R$ $R = 121$Ohms. Since the bulbs are connected in series, and there are three bulbs, the voltage across each bulb will be a third of the source voltage, so $P = (110/3)^2 /121$ $P = 11.111W$
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