## Fundamentals of Electrical Engineering

$P = 11.111W$
First calculate the resistance of the bulb. $P = V^2 /R$ $100 = 110^2/R$ $R = 121$Ohms. Since the bulbs are connected in series, and there are three bulbs, the voltage across each bulb will be a third of the source voltage, so $P = (110/3)^2 /121$ $P = 11.111W$