Electrical Engineering: Principles & Applications (6th Edition)

Published by Prentice Hall
ISBN 10: 0133116646
ISBN 13: 978-0-13311-664-9

Chapter 1 - 1.7 - Problems - Introduction to Circuits - Page 40: P1.77


$I_{ab} = 0 A $ The equivalent current source is $5A$.

Work Step by Step

The two points, a and b, are not connected within a closed loop. Thus, it follows that the current through them is $\fbox{0A}$. We now must find the equivalent current source. Thus, we use Ohm's law to find the equivalent current: $I = \frac{V}{R} = \frac{10V}{2 \Omega} = \fbox{5A}$ Thus, the equivalent current source has a current of 5 Amps.
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