Electrical Engineering: Principles & Applications (6th Edition)

Published by Prentice Hall
ISBN 10: 0133116646
ISBN 13: 978-0-13311-664-9

Chapter 1 - 1.7 - Problems - Introduction to Circuits: P1.63



Work Step by Step

Ohm's law dictates $v_2=5V$ and since all three resistors are in parallel we can find that $i_2=v_2\div 10\Omega=.5A$ and $i_3=v_2\div5\Omega=1A$ Then, using KCL in conjunction with Ohm's law, $v_1=5\Omega\times(1A+1A+0.5A)=12.5V$ Finally, with KVL we can find $v_x-v_1-v_2=0, v_x=12.5V+5V=17.5V$
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