Electrical Engineering: Principles & Applications (6th Edition)

Published by Prentice Hall
ISBN 10: 0133116646
ISBN 13: 978-0-13311-664-9

Chapter 1 - 1.7 - Problems - Introduction to Circuits - Page 40: P1.76


$ V = 20 V$

Work Step by Step

We are told that the current is 10 Amps and that the Resistance is $2 \Omega$. Thus, we use Ohm's Law to obtain: $V = IR = (10A)(2 \Omega) = \fbox{20V}$ Thus, it follows that the missing element is a $\underline{20V \ voltage \ source.}$
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