## Electrical Engineering: Principles & Applications (6th Edition)

$V = 20 V$
We are told that the current is 10 Amps and that the Resistance is $2 \Omega$. Thus, we use Ohm's Law to obtain: $V = IR = (10A)(2 \Omega) = \fbox{20V}$ Thus, it follows that the missing element is a $\underline{20V \ voltage \ source.}$