Answer
$I_R= 2A$
$P_V = 20W$
$P_I = -40W$
Work Step by Step
This is a series circuit, so the current across the entire thing is equal. Thus, we find that the current through the resistor is: $I_R = \fbox{2A}$. We know that power through a resistor is given by: $P=I^2R$. Thus, we find:
$P_R = 2^2\times(5) = 4\times 5=\fbox{20W}$
We now use Kirchhoff's law to find the voltage of the voltage source:
$V +10+10 = 0 \\ V=-20V$
From this, we find power:
$P_V = VI = -20 \times 2 = \fbox{-40W}$
