Answer
(a) $1.15\times 10^5J$
(b) $170m$
Work Step by Step
(a) We can find the required energy as
$E=W=Pt$
We plug in the known values to obtain:
$E=(1.33)(24h\times 3600s/h)$
$E=1.15\times 10^5J$
(b) We know that
$W=mgh$
This can be rearranged as:
$h=\frac{W}{mg}$
We plug in the known values to obtain:
$h=\frac{1.15\times 10^5}{70(9.8)}$
$h=170m$
