Answer
$2.20\frac{m}{s}$
Work Step by Step
We can find the required speed as follows:
$F=mg$
$\implies F=(5)(9.8)=49N$
We know that
$P=Fv$
This can be rearranged as:
$v=\frac{P}{F}$
We plug in the known values to obtain:
$v=\frac{108}{49}=2.20\frac{m}{s}$
