Answer
$v_o=74m/s$
Work Step by Step
According to the work-energy theorem, work is equal to the change in kinetic energy. This means that $$W=\Delta KE$$ To find work, use the formula $$W=Fd$$ Substituting known values of $F=65N$ and $d=2.3cm=0.023m$ yields a work of $$W=(65N)(0.023m)=1.5J$$ Use the kinetic energy formula $$K=W=\frac{1}{2}mv^2$$ to solve for velocity. $$W=\frac{1}{2}mv^2$$ $$v=\sqrt{\frac{2W}{m}}$$ Substituting known values of $W=1.5J$ and $m=0.55g=0.00055kg$ yields a velocity of $$v=\sqrt{\frac{2(1.5J)}{0.00055kg}}=74m/s$$
