Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 213: 58

Answer

$6.0\times 10^{-20}J$

Work Step by Step

We can find the required work done as follows: $W=Fd$ We plug in the known values to obtain: $W=(7.5\times 10^{-12})(8.0\times 10^{-9})$ $W=6.0\times 10^{-20}J$
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