Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 213: 45

Answer

$0.32mW$

Work Step by Step

We know that $P=Fv$ We plug in the known values to obtain: $P=(mg)(v)$ $P=(1.4\times 10^{-3})(9.81)(0.023)$ $P=3.2\times 10^{-4}W=0.32mW$
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