Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 213: 48

Answer

$0.143hp$

Work Step by Step

As we know that $P=\frac{W}{t}$ but $W=mgh$ $\implies P=\frac{mgh}{t}$ We plug in the known values to obtain: $P=\frac{(12.0lb\times 4.448\frac{N}{lb})(2.00m)}{1.00s}$ $P=107W\times \frac{1hp}{746W}=0.143hp$
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