Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 213: 59

Answer

(a) $630N$ (b) $76W$

Work Step by Step

(a) We can find the required force as $F=\frac{W}{d}$ We plug in the known values to obtain: $F=\frac{19J}{0.030m}$ $F=630N$ (b) We can find the required power as $P=\frac{W}{t}$ We plug in the known values to obtain: $P=\frac{19}{0.25}$ $P=76W$
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