Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 6 - Applications of Newton's Laws - Problems and Conceptual Exercises - Page 183: 67

Answer

$A\lt C \lt B$

Work Step by Step

We know that For A $\frac{a_{c,new}}{a_{c,old}}=\frac{v_{new}^2/r_{new}^2}{v_{old}^2/r_{old}^2}=(\frac{v_{new}}{v_{old}})^2(\frac{r_{old}}{r_{new}})=(\frac{v_{old}}{v_{old}})^2(\frac{r_{old}}{\frac{1}{2}r_{old}})=2$ For B $\frac{a_{c,new}}{a_{c,old}}=\frac{v_{new}^2/r_{new}^2}{v_{old}^2/r_{old}^2}=(\frac{v_{new}}{v_{old}})^2(\frac{r_{old}}{r_{new}})=(\frac{\frac{1}{3}v_{old}}{v_{old}})^2(\frac{r_{old}}{r_{old}})=\frac{1}{9}$ For C $\frac{a_{c,new}}{a_{c,old}}=\frac{v_{new}^2/r_{new}^2}{v_{old}^2/r_{old}^2}=(\frac{v_{new}}{v_{old}})^2(\frac{r_{old}}{r_{new}})=(\frac{v_{old}}{v_{old}})^2(\frac{r_{old}}{4r_{old}})=\frac{1}{4}$ Now we can rank A, B and C in order of decreasing centripetal acceleration as $A\lt C \lt B$
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