Answer
$1.4\times 10^5\frac{m}{s^2}$
Work Step by Step
We can find the centripetal acceleration as follows:
$a_c=\frac{v^2}{r}$
We plug in the known values to obtain:
$a_c=\frac{(77)^2}{0.042}$
$a_c=1.4\times 10^5\frac{m}{s^2}$
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