Answer
(a) $0.83KN$
(b) $1.3KN$
Work Step by Step
(a) We can find the required tension as follows:
$T=mg+\frac{mv^2}{r}$
$\implies T=m(g+\frac{v^2}{r})$
We plug in the known values to obtain:
$T=(63)[9.81+\frac{(4.8)^2}{6.9}]$
$T=828N=0.83KN$
(b) We can find the required tension as follows:
$T=mg+\frac{mv^2}{r}$
$\implies T=m(g+\frac{v^2}{r})$
We plug in the known values to obtain:
$T=(126)[9.81+\frac{(2.4)^2}{6.9}]$
$T=1300N=1.3KN$
