Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 6 - Applications of Newton's Laws - Problems and Conceptual Exercises - Page 183: 62

Answer

$380N$

Work Step by Step

We can find the apparent weight as follows: $\Sigma F_y=N-mg$ $\implies -ma_c=N-mg$ $\implies -m(\frac{v^2}{r})=N-mg$ This simplifies to: $N=m(g-\frac{v^2}{r})$ We plug in the known values to obtain: $N=(67)(9.81-\frac{(12)^2}{35})$ $N=380N$
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