Answer
$380N$
Work Step by Step
We can find the apparent weight as follows:
$\Sigma F_y=N-mg$
$\implies -ma_c=N-mg$
$\implies -m(\frac{v^2}{r})=N-mg$
This simplifies to:
$N=m(g-\frac{v^2}{r})$
We plug in the known values to obtain:
$N=(67)(9.81-\frac{(12)^2}{35})$
$N=380N$