Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 6 - Applications of Newton's Laws - Problems and Conceptual Exercises - Page 183: 73

Answer

$5.62Kg$

Work Step by Step

We know that $\Sigma F_y=-Ky-mg=0$ This simplifies to: $m=-\frac{K}{g}$ We plug in the known values to obtain: $m=-\frac{(1750)(-0.0315)}{9.81}$ $m=5.62Kg$
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