Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 6 - Applications of Newton's Laws - Problems and Conceptual Exercises - Page 183: 74

Answer

$14^{\circ}$

Work Step by Step

We can find the required angle as follows: $\Sigma F_y=N-mgcos\theta=0$ $\implies N=mgcos\theta$ Similarly $\Sigma F_x=mgsin\theta-f_s=0$ $\implies mgsin\theta-\mu_s (mgcos\theta)=0$ $\implies \mu_scos\theta=sin\theta$ This simplifies to: $\theta=tan^{-1}(\mu_s)$ We plug in the known values to obtain: $\theta=tan^{-1}(0.25)$ $\theta=14^{\circ}$
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